Question:
A block of weight $W$ rests on a horizontal floor with coefficient of static friction $\mu$. It is desired to make the block move by applying minimum amount of force. The angle $\theta$ from the horizontal at which the force should be applied and magnitude of the force $F$ are respectively.
$\theta=\tan ^{-1}(\mu), F=\frac{\mu W}{\sqrt{1+\mu^{2}}}$
$\theta=\tan ^{-1}\left(\frac{1}{\mu}\right), F=\frac{\mu W}{\sqrt{1+\mu^{2}}}$
$\theta=0, F=\mu W$
$\theta=\tan ^{-1}\left(\frac{\mu}{1+\mu}\right), F=\frac{\mu W}{1+\mu}$
Question of from chapter.
JEE Main Previous Year May 19, 2012
Correct Option: 1
Solution:
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