# A body of mass $5 \mathrm{~kg}$ under the action of constant force $\overrightarrow{\mathrm{F}}=\mathrm{F}_{\mathrm{x}} \hat{\mathrm{i}}+\mathrm{F}_{\mathrm{y}} \hat{\mathrm{j}}$ has velocity at $\mathrm{t}=0 \mathrm{~s}$ as $\overrightarrow{\mathrm{v}}=(6 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}) \mathrm{m} / \mathrm{s}$ and $a t=10 s$ as $\vec{v}=+6 \hat{j} \mathrm{~m} / \mathrm{s}$. The force $\vec{F}$ is:

Question:

A body of mass $5 \mathrm{~kg}$ under the action of constant force $\overrightarrow{\mathrm{F}}=\mathrm{F}_{\mathrm{x}} \hat{\mathrm{i}}+\mathrm{F}_{\mathrm{y}} \hat{\mathrm{j}}$ has velocity at $\mathrm{t}=0 \mathrm{~s}$ as $\overrightarrow{\mathrm{v}}=(6 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}) \mathrm{m} / \mathrm{s}$ and $a t=10 s$ as $\vec{v}=+6 \hat{j} \mathrm{~m} / \mathrm{s}$. The force $\vec{F}$ is:

1. $(-3 \hat{\mathrm{j}}+4 \hat{\mathrm{j}}) \mathrm{N}$

2. $\left(-\frac{3}{5} \hat{\mathrm{i}}+\frac{4}{5} \hat{\mathrm{j}}\right) \mathrm{N}$

3. $(3 \hat{i}-4 \hat{j}) \mathrm{N}$

4. $\left(\frac{3}{5} \hat{i}-\frac{4}{5} \hat{j}\right) \mathrm{N}$

JEE Main Previous Year Single Correct Question of JEE Main from Physics Laws of Motion chapter.

JEE Main Previous Year April 11, 2014

Correct Option: 1

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