**Question:**

**A body of mass starts moving from rest along $x$-axis so that its velocity varies as $\mathrm{v}=\mathrm{a} \sqrt{\mathrm{s}}$ where $\mathrm{a}$ is a constant $\mathrm{s}$ and is the distance covered by the body. The total work done by all the forces acting on the body in the first second after the start of the motion is:**

$\frac{1}{8} m a^{4} t^{2}$

$4 m a^{4} t^{2}$

$8 \mathrm{ma}^{4} \mathrm{t}^{2}$

$\frac{1}{4} m a^{4} t^{2}$

Question of from chapter.

JEE Main Previous Year April 16, 2018

Correct Option: 1

**Solution:**