A heavy box is to dragged along a rough horizontal floor. To do so, person A pushes it at an angle $30^{\circ}$ from the horizontal and requires a minimum force $\mathrm{F}_{\mathrm{A}}$, while person B pulls the box at an angle $60^{\circ}$ from the horizontal and needs minimum force $F_{B}$. If the coefficient of friction between the box and the floor is $\frac{\sqrt{3}}{5}$, the ratio $\frac{\mathrm{F}_{\mathrm{A}}}{\mathrm{F}_{\mathrm{B}}}$ is

Question:

A heavy box is to dragged along a rough horizontal floor. To do so, person A pushes it at an angle $30^{\circ}$ from the horizontal and requires a minimum force $\mathrm{F}_{\mathrm{A}}$, while person B pulls the box at an angle $60^{\circ}$ from the horizontal and needs minimum force $F_{B}$. If the coefficient of friction

between the box and the floor is $\frac{\sqrt{3}}{5}$, the ratio $\frac{\mathrm{F}_{\mathrm{A}}}{\mathrm{F}_{\mathrm{B}}}$ is

  1. $\sqrt{3}$

  2. $\frac{5}{\sqrt{3}}$

  3. $\sqrt{\frac{3}{2}}$

  4. $\frac{2}{\sqrt{3}}$

JEE Main Previous Year Single Correct Question of JEE Main from Physics Laws of Motion chapter.

JEE Main Previous Year April 19, 2014


Correct Option: 4

Solution:

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