Question:
A mass of $10 \mathrm{~kg}$ is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of $45^{\circ}$ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is $\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)$
$200 \mathrm{~N}$
$140 \mathrm{~N}$
$70 \mathrm{~N}$
$100 \mathrm{~N}$
Question of from chapter.
JEE Main Previous Year 9 Jan. 2019
Correct Option: 4
Solution:
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