**Question:**

**A neutron moving with a speed ‘v’ makes a head on collision with a stationary hydrogen atom in ground state. The minimum kinetic energy of the neutron for which inelastic collision will take place is :**

$20.4 \mathrm{eV}$

$10.2 \mathrm{eV}$

$12.1 \mathrm{eV}$

$16.8 \mathrm{eV}$

Question of from chapter.

JEE Main Previous Year April 10, 2016

Correct Option: 1

**Solution:**

### Related Questions

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