A particle is released on a vertical smooth semicircular track from point $X$ so that $O X$ makes angle $\theta$ from the vertical (see figure). The normal reaction of the track on the particle vanishes at point $Y$ where $O Y$ makes angle $\phi$ with the horizontal. Then:

Question:

A particle is released on a vertical smooth semicircular track from point $X$ so that $O X$ makes angle $\theta$ from the vertical (see figure). The normal reaction of the track on the particle vanishes at point $Y$ where $O Y$ makes angle $\phi$ with the horizontal. Then:

1. $\sin \phi=\cos \phi$

2. $\sin \phi=\frac{1}{2} \cos \theta$

3. $\sin \phi=\frac{2}{3} \cos \theta$

4. $\sin \phi=\frac{3}{4} \cos \theta$

JEE Main Previous Year Single Correct Question of JEE Main from Physics Laws of Motion chapter.

JEE Main Previous Year April 19, 2014

Correct Option: 3

Solution:

(3)

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