Question:
A particle of mass $\mathrm{m}$ is moving in a straight line with momentum $p$. Starting at time $t=0$, a force $F=k$ t acts in the same direction on the moving particle during time interval T so that its momentum changes from $p$ to $3 p .$ Here $k$ is a constant. The value of $\mathrm{T}$ is :
$2 \sqrt{\frac{k}{\mathrm{p}}}$
$2 \sqrt{\frac{p}{k}}$
$\sqrt{\frac{2 k}{\mathrm{p}}}$
$\sqrt{\frac{2 p}{\mathrm{k}}}$
Question of from chapter.
JEE Main Previous Year 11 Jan. 2019
Correct Option: 2
Solution:
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