# A particle of mass $\mathrm{m}$ is moving in a straight line with momentum $p$. Starting at time $t=0$, a force $F=k$ t acts in the same direction on the moving particle during time interval T so that its momentum changes from $p$ to $3 p .$ Here $k$ is a constant. The value of $\mathrm{T}$ is :

Question:

A particle of mass $\mathrm{m}$ is moving in a straight line with momentum $p$. Starting at time $t=0$, a force $F=k$ t acts in the same direction on the moving particle during time interval T so that its momentum changes from $p$ to $3 p .$ Here $k$ is a constant. The value of $\mathrm{T}$ is :

1. $2 \sqrt{\frac{k}{\mathrm{p}}}$

2. $2 \sqrt{\frac{p}{k}}$

3. $\sqrt{\frac{2 k}{\mathrm{p}}}$

4. $\sqrt{\frac{2 p}{\mathrm{k}}}$

JEE Main Previous Year Single Correct Question of JEE Main from Physics Laws of Motion chapter.

JEE Main Previous Year 11 Jan. 2019

Correct Option: 2

Solution:

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