A quantity $x$ is given by $\left(I F v^{2} / W L^{4}\right)$ in terms of moment of inertia $I$, force $F$, velocity $v$, work $W$ and Length $L$. The dimensional formula for $x$ is same as that of :

Question:

A quantity $x$ is given by $\left(I F v^{2} / W L^{4}\right)$ in terms of moment of inertia $I$, force $F$, velocity $v$, work $W$ and Length $L$. The dimensional formula for $x$ is same as that of :

  1. planck’s constant

  2. force constant

  3. energy density

  4. coefficient of viscosity

JEE Main Previous Year Single Correct Question of JEE Main from Chemistry Laws of Motion chapter.

JEE Main Previous Year 2020


Correct Option: 3

Solution:

Dimension of Force $F=\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-2}$

Dimension of velocity $V=\mathrm{L}^{1} \mathrm{~T}^{-1}$

Dimension of work $=M^{1} L^{2} T^{-2}$

Dimension of length $=\mathrm{L}$.

Moment of inertia $=\mathrm{ML}^{2}$

$\therefore x=\frac{I F v^{2}}{W L^{4}}$

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