Question:
A quantity $x$ is given by $\left(I F v^{2} / W L^{4}\right)$ in terms of moment of inertia $I$, force $F$, velocity $v$, work $W$ and Length $L$. The dimensional formula for $x$ is same as that of :
planck’s constant
force constant
energy density
coefficient of viscosity
Question of from chapter.
JEE Main Previous Year 2020
Correct Option: 3
Solution:
Dimension of Force $F=\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-2}$
Dimension of velocity $V=\mathrm{L}^{1} \mathrm{~T}^{-1}$
Dimension of work $=M^{1} L^{2} T^{-2}$
Dimension of length $=\mathrm{L}$.
Moment of inertia $=\mathrm{ML}^{2}$
$\therefore x=\frac{I F v^{2}}{W L^{4}}$
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