# A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of $10^{12} / \mathrm{sec}$. What is the force constant of the bonds connecting one atom with the other? (Mole wt. of silver $=108$ and Avagadro number $=6.02 \times 10^{23} \mathrm{gm}$ mole $^{-1}$ )

Question:

A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of $10^{12} / \mathrm{sec}$. What is the force constant of the bonds connecting one atom with the other? (Mole wt. of silver $=108$ and Avagadro number $=6.02 \times 10^{23} \mathrm{gm}$ mole $^{-1}$ )

1. $6.4 \mathrm{~N} / \mathrm{m}$

2. $7.1 \mathrm{~N} / \mathrm{m}$

3. $2.2 \mathrm{~N} / \mathrm{m}$

4. $5.5 \mathrm{~N} / \mathrm{m}$

JEE Main Previous Year Single Correct Question of JEE Main from Physics Oscillations chapter.

JEE Main Previous Year 2018

Correct Option: 2

Solution:

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