Question:
A spring of force constant $800 \mathrm{~N} / \mathrm{m}$ has an extension of $5 \mathrm{~cm}$. The work done in extending it from $5 \mathrm{~cm}$ to $15 \mathrm{~cm}$ is
$16 \mathrm{~J}$
$8 \mathrm{~J}$
$32 \mathrm{~J}$
$24 \mathrm{~J}$
Question of from chapter.
JEE Main Previous Year 2002
Correct Option: 2
Solution:
Related Questions
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