An inductance coil has a reactance of 100 W. When an AC signal of frequency 1000 Hz is applied to the coil, the applied voltage leads the current by 45°. The self-inductance of the coil is

Question:

An inductance coil has a reactance of $100 \Omega$. When an AC signal of frequency $1000 \mathrm{~Hz}$ is applied to the coil, the applied voltage leads the current by $45^{\circ}$. The self-inductance of the coil is :

  1. $1.1 \times 10^{-2} \mathrm{H}$

  2. $1.1 \times 10^{-1} \mathrm{H}$

  3. $5.5 \times 10^{-5} \mathrm{H}$

  4. $6.7 \times 10^{-7} \mathrm{H}$


Correct Option: 1

JEE Main Previous Year 1 Question of JEE Main from Physics Alternating Current chapter.
JEE Main Previous Year Sep. 02, 2020 (II)

Solution:

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