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Question:

A wire carrying current $\mathrm{I}$ is tied between points $\mathrm{P}$ and $\mathrm{Q}$ and is in the shape of a circular arc of radius $\mathrm{R}$ due to a uniform magnetic field B (perpendicular to the plane of the paper, shown by $x x x$ ) in the vicinity of the wire. If the wire subtends an angle $2 \theta_{0}$ at the centre of the circle (of which it forms an arc) then the tension in the wire is:

1. $\frac{\text { IBR }}{2 \sin \theta_{0}}$

2. $\frac{\text { IBR } \theta_{0}}{\sin \theta_{0}}$

3. IBR

4. $\frac{\text { IBR }}{\sin \theta_{0}}$

Correct Option: 3

JEE Main Previous Year 1 Question of JEE Main from Physics Moving Charges and Magnetism chapter.
JEE Main Previous Year Online April 11, 2015

Solution:

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