# Cp”gngevtqp”ku”oqxkpi”cnqpi”-“x”fktgevkqp”ykvj”c”xgnqekv{ qh”8″Ù”328 “ou30″Kv”gpvgtu”c”tgikqp”qh”wpkhqto”gngevtke”hkgnf”qh 522″X1eo”rqkpvkpi”cnqpi”-“y”fktgevkqp0″Vjg”ocipkvwfg”cpf fktgevkqp”qh”vjg”ocipgvke”hkgnf”ugv”wr”kp”vjku”tgikqp”uwej vjcv”vjg”gngevtqp”mggru”oqxkpi”cnqpi”vjg”x”fktgevkqp”yknn dg”<

Question:

An electron is moving along $+x$ direction with a velocity of $6 \times 10^{6} \mathrm{~ms}^{-1}$. It enters a region of uniform electric field of $300 \mathrm{~V} / \mathrm{cm}$ pointing along $+y$ direction. The magnitude and direction of the magnetic field set up in this region such that the electron keeps moving along the $x$ direction will be:

1. $3 \times 10^{-4} \mathrm{~T}$, along $+z$ direction

2. $5 \times 10^{-3} \mathrm{~T}$, along $-z$ direction

3. $5 \times 10^{-3} \mathrm{~T}$, along $+z$ direction

4. $3 \times 10^{-4} \mathrm{~T}$, along $-z$ direction

Correct Option: 3

JEE Main Previous Year 1 Question of JEE Main from Physics Moving Charges and Magnetism chapter.
JEE Main Previous Year Sep. 06, 2020 (I)

Solution:

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# Cp”gngevtqp”ku”oqxkpi”cnqpi”-“x”fktgevkqp”ykvj”c”xgnqekv{ qh”8″Ù”328 “ou30″Kv”gpvgtu”c”tgikqp”qh”wpkhqto”gngevtke”hkgnf”qh 522″X1eo”rqkpvkpi”cnqpi”-“y”fktgevkqp0″Vjg”ocipkvwfg”cpf fktgevkqp”qh”vjg”ocipgvke”hkgnf”ugv”wr”kp”vjku”tgikqp”uwej vjcv”vjg”gngevtqp”mggru”oqxkpi”cnqpi”vjg”x”fktgevkqp”yknn dg”<

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Question:

An electron is moving along $+x$ direction with a velocity of $6 \times 10^{6} \mathrm{~ms}^{-1}$. It enters a region of uniform electric field of $300 \mathrm{~V} / \mathrm{cm}$ pointing along $+y$ direction. The magnitude and direction of the magnetic field set up in this region such that the electron keeps moving along the $x$ direction will be:

1. $3 \times 10^{-4} \mathrm{~T}$, along $+z$ direction

2. $5 \times 10^{-3} \mathrm{~T}$, along $-z$ direction

3. $5 \times 10^{-3} \mathrm{~T}$, along $+z$ direction

4. $3 \times 10^{-4} \mathrm{~T}$, along $-z$ direction

Correct Option: 3

JEE Main Previous Year 1 Question of JEE Main from Physics Moving Charges and Magnetism chapter.
JEE Main Previous Year Sep. 06, 2020 (I)

Solution:

# Cp”gngevtqp”ku”oqxkpi”cnqpi”-“x”fktgevkqp”ykvj”c”xgnqekv{ qh”8″Ù”328 “ou30″Kv”gpvgtu”c”tgikqp”qh”wpkhqto”gngevtke”hkgnf”qh 522″X1eo”rqkpvkpi”cnqpi”-“y”fktgevkqp0″Vjg”ocipkvwfg”cpf fktgevkqp”qh”vjg”ocipgvke”hkgnf”ugv”wr”kp”vjku”tgikqp”uwej vjcv”vjg”gngevtqp”mggru”oqxkpi”cnqpi”vjg”x”fktgevkqp”yknn dg”<

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Question:

An electron is moving along $+x$ direction with a velocity of $6 \times 10^{6} \mathrm{~ms}^{-1}$. It enters a region of uniform electric field of $300 \mathrm{~V} / \mathrm{cm}$ pointing along $+y$ direction. The magnitude and direction of the magnetic field set up in this region such that the electron keeps moving along the $x$ direction will be:

1. $3 \times 10^{-4} \mathrm{~T}$, along $+z$ direction

2. $5 \times 10^{-3} \mathrm{~T}$, along $-z$ direction

3. $5 \times 10^{-3} \mathrm{~T}$, along $+z$ direction

4. $3 \times 10^{-4} \mathrm{~T}$, along $-z$ direction

Correct Option: 3

JEE Main Previous Year 1 Question of JEE Main from Physics Moving Charges and Magnetism chapter.
JEE Main Previous Year Sep. 06, 2020 (I)

Solution:

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