Question:
Figure shows elliptical path abed of a planet around the sun $S$ such that the area of triangle csa is $\frac{1}{4}$ the area of the ellipse. (See figure) With db as the semimajor axis, and ca as the semiminor axis. If $\mathrm{t}_{1}$ is the time taken for planet to go over path $a b c$ and $t_{2}$ for path taken over cda then:
$\mathrm{t}_{1}=4 \mathrm{t}_{2}$
$\mathrm{t}_{1}=2 \mathrm{t}_{2}$
$\mathrm{t}_{1}=3 \mathrm{t}_{2}$
$\mathrm{t}_{1}=\mathrm{t}_{2}$
Question of from chapter.
JEE Main Previous Year April 9, 2016
Correct Option: 3
Solution: