# For a particle in uniform circular motion, the acceleration $\vec{a}$ at a point $\mathrm{P}(\mathrm{R}, \theta)$ on the circle of radius $\mathrm{R}$ is (Here $\theta$ is measured from the $x$-axis)

Question:

For a particle in uniform circular motion, the acceleration $\vec{a}$ at a point $\mathrm{P}(\mathrm{R}, \theta)$ on the circle of radius $\mathrm{R}$ is (Here $\theta$ is measured from the $x$-axis)

1. $-\frac{v^{2}}{R} \cos \theta \hat{i}+\frac{v^{2}}{R} \sin \theta \hat{j}$

2. $-\frac{v^{2}}{R} \sin \theta \hat{i}+\frac{v^{2}}{R} \cos \theta \hat{j}$

3. $-\frac{v^{2}}{R} \cos \theta \hat{i}-\frac{v^{2}}{R} \sin \theta \hat{j}$

4. $\frac{v^{2}}{R} \hat{i}+\frac{v^{2}}{R} \hat{j}$

JEE Main Previous Year Single Correct Question of JEE Main from Physics Laws of Motion chapter.

JEE Main Previous Year 2010

Correct Option: 3

Solution:

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