For a transistor amplifier in common emitter configuration for load impedance of 1k W ( 50 and 25) fe oe h h = = the current gain is

Question:
For a transistor amplifier in common emitter configuration for load impedance of $1 \mathrm{k} \Omega \quad\left(h_{f e}=50\right.$ and $\left.h_{o e}=25\right)$ the current gain is

$-24.8$
$-15.7$
$-5.2$
$-48.78$

Correct Option: 4

JEE Main Previous Year 1 Question of JEE Main from Physics Semiconductors chapter.

JEE Main Previous Year 2004

Solution:

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