For any , 4 2 æ ö p p qÎç ÷ è ø the expression 3(sinq – cosq) 4 + 6(sinq + cosq) 2 + 4sin6q equals:

Question:
For any $\theta \in\left(\frac{\pi}{4}, \frac{\pi}{2}\right)$ the expression $3(\sin \theta-\cos \theta)^{4}+6(\sin \theta+\cos \theta)^{2}+4 \sin ^{6} \theta$ equals:

$13-4 \cos ^{2} \theta+6 \sin ^{2} \theta \cos ^{2} \theta$
$13-4 \cos ^{6} \theta$
$13-4 \cos ^{2} \theta+6 \cos ^{4} \theta$
$13-4 \cos ^{4} \theta+2 \sin ^{2} \theta \cos ^{2} \theta$

Correct Option: 2

JEE Main Previous Year 1 Question of JEE Main from Mathematics Trigonometry chapter.

JEE Main Previous Year Jan. 9, 2019 (I)

Solution:

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