For $x \in R, x \neq 0$, let $f_{0}(x)=\frac{1}{1-x}$ and $f_{n+1}(x)=f_{0}\left(f_{n}(x)\right)$, $\mathrm{n}=0,1,2, \ldots .$ Then the value of $\mathrm{f}_{100}(3)+\mathrm{f}_{1}\left(\frac{2}{3}\right)+\mathrm{f}_{2}\left(\frac{3}{2}\right)$ is equal to:
Correct Option: 3
Download now India’s Best Exam Preparation App
Class 9-10, JEE & NEET
Related Questions
Let $R_{1}$ and $R_{2}$ be two relations defined as follows :
$R_{1}=\left\{(a, b) \in \mathbf{R}^{2}: a^{2}+b^{2} \in Q\right\}$ and
$R_{2}=\left\{(a, b) \in \mathbf{R}^{2}: a^{2}+b^{2} \notin Q\right\}$, where $Q$ is the set of all rational numbers. Then :
The domain of the function $f(x)=\sin ^{-1}\left(\frac{|x|+5}{x^{2}+1}\right)$ is $(-\infty,-a] \cup[a, \infty]$. Then $a$ is equal to :
If $R=\left\{(x, y): x, y \in \mathbf{Z}, x^{2}+3 y^{2} \leq 8\right\}$ is a relation on the set of integers $\mathbf{Z}$, then the domain of $R^{-1}$ is :
If $R=\left\{(x, y): x, y \in \mathbf{Z}, x^{2}+3 y^{2} \leq 8\right\}$ is a relation on the set of integers $\mathbf{Z}$, then the domain of $R^{-1}$ is :
Let $f: R \rightarrow R$ be defined by $f(x)=\frac{x}{1+x^{2}}, x \in R$. Then the range of $f$ is :
The domain of the definition of the function $f(x)=\frac{1}{4-x^{2}}+\log _{10}\left(x^{3}-x\right)$ is:
The range of the function $f(x)=\frac{x}{1+|x|}, x \in R$, is is
The domain of the function $f(x)=\frac{1}{\sqrt{|x|-x}}$ is
Domain of definition of the function $f(x)=\frac{3}{4-x^{2}}+\log _{10}\left(x^{3}-x\right)$, is
Let $[t]$ denote the greatest integer $\leq t$. Then the equation in $x,[x]^{2}+2[x+2]-7=0$ has :