**Question:**

If $X=\left\{4^{n}-3 n-1: n \in N\right\}$ and $Y=\{9(n-1): n \in N\}$, where $N$ is the set of natural numbers, then $X \cup Y$ is equal to:

Correct Option: 2

JEE Main Previous Year 2014

**Solution:**

If $X=\left\{4^{n}-3 n-1: n \in N\right\}$ and $Y=\{9(n-1): n \in N\}$, where $N$ is the set of natural numbers, then $X \cup Y$ is equal to:

Correct Option: 2

JEE Main Previous Year 2014
**Solution:**