If a bÎ , C are the distinct roots, of the equation 2 x x10 – += , then 101 107 a +b is equal to :

Question:

If $\alpha, \beta \in \mathrm{C}$ are the distinct roots, of the equation $x^{2}-x+1=0$, then $\alpha^{101}+\beta^{107}$ is equal to :

  1. 0

  2. 1

  3. 2

  4. $-1$


Correct Option: 2

JEE Main Previous Year 1 Question of JEE Main from Mathematics Complex Numbers and Quadratic Equations chapter.
JEE Main Previous Year 2018

Solution:

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