# If a = cos–1 3 5 æ ö ç ÷ è ø , b = tan–1 1 3 æ ö ç ÷ è ø , where 0 < a, b < 2 p , then a – b is equal to :

Question:

If $\alpha=\cos ^{-1}\left(\frac{3}{5}\right), \beta=\tan ^{-1}\left(\frac{1}{3}\right)$, where $0<\alpha, \beta<\frac{\pi}{2}$, then $\alpha-\beta$ is equal to:

1. $\tan ^{-1}\left(\frac{9}{5 \sqrt{10}}\right)$

2. $\cos ^{-1}\left(\frac{9}{5 \sqrt{10}}\right)$

3. $\tan ^{-1}\left(\frac{9}{14}\right)$

4. $\sin ^{-1}\left(\frac{9}{5 \sqrt{10}}\right)$

Correct Option: 4

JEE Main Previous Year 1 Question of JEE Main from Mathematics Inverse Trigonometric Functions chapter.
JEE Main Previous Year April 8, 2019 (I)

Solution:

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