If a1 , a2 , a3 , ….. an are in A.P. and a1 + a4 + a7 + ….+ a16 = 114, then a1 + a6 + a11 + a16 is equal to :

Question:

If $a_{1}, a_{2}, a_{3}, \ldots . . a_{n}$ are in A.P. and $a_{1}+a_{4}+a_{7}+\ldots+a_{16}=114$, then $a_{1}+a_{6}+a_{11}+a_{16}$ is equal to: 

  1. 98

  2. 76

  3. 38

  4. 64


Correct Option: 2

JEE Main Previous Year 1 Question of JEE Main from Mathematics Sequences and Series chapter.
JEE Main Previous Year April 10, 2019(I)

Solution:

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