Question:
If, for a positive integer $n$, the quadratic equation,
$$
x(x+1)+(x+1)(x+2)+\ldots . .+(x+\overline{n-1})(x+n)=10 n
$$
has two consecutive integral solutions, then $n$ is equal to:
Correct Option: 1
JEE Main Previous Year 2017
Solution:
If, for a positive integer $n$, the quadratic equation,
$$
x(x+1)+(x+1)(x+2)+\ldots . .+(x+\overline{n-1})(x+n)=10 n
$$
has two consecutive integral solutions, then $n$ is equal to:
Correct Option: 1