If, for a positive integer n, the quadratic equation, x(x + 1) + (x + 1) (x + 2) + ….. + (x + n 1- ) (x + n) = 10n has two consecutive integral solutions, then n is equal to:

Question:

If, for a positive integer $n$, the quadratic equation,

$$

x(x+1)+(x+1)(x+2)+\ldots . .+(x+\overline{n-1})(x+n)=10 n

$$

has two consecutive integral solutions, then $n$ is equal to:

  1. 11

  2. 12

  3. 9

  4. 10


Correct Option: 1

JEE Main Previous Year 1 Question of JEE Main from Mathematics Complex Numbers and Quadratic Equations chapter.
JEE Main Previous Year 2017

Solution:

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