If l be the ratio of the roots of the quadratic equation in x, 3m2x 2 + m(m – 4)x + 2 = 0, then the least value of m for which 1 l 1, l + = is :

Question:
If $\lambda$ be the ratio of the roots of the quadratic equation in $\mathrm{x}$, $3 m^{2} x^{2}+m(m-4) x+2=0$, then the least value of $m$ for which $\lambda+\frac{1}{\lambda}=1$, is :

$2-\sqrt{3}$
$4-3 \sqrt{2}$
$-2+\sqrt{2}$
$4-2 \sqrt{3}$

Correct Option: 2

JEE Main Previous Year 1 Question of JEE Main from Mathematics Complex Numbers and Quadratic Equations chapter.

JEE Main Previous Year Jan. 12, 2019 (I)

Solution:

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