If the 7th term in the binomial expansion of 9 3 3 3 ln , 0, 84 x x æ ö ç ÷ + > è ø is equal to 729, then x can be :

Question:
If the 7 th term in the binomial expansion of $\left(\frac{3}{\sqrt[3]{84}}+\sqrt{3} \ln x\right)^{9}, x>0$, is equal to 729 , then $x$ can be :

$e^{2}$
$e$
$\frac{e}{2}$
$2 e$

Correct Option: 2

JEE Main Previous Year 1 Question of JEE Main from Mathematics Binomial Theorem and its Simple Applications chapter.

JEE Main Previous Year Online April 22, 2013

Solution:

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