If the coefficients of x2 and x3 are both ero, in the expansion of the expression (1 + ax + bx2 ) (1–3x)15 in powers of x, then the ordered pair (a, b) is equal to:


If the coefficients of $\mathrm{x}^{2}$ and $\mathrm{x}^{3}$ are both zero, in the expansion of the expression $\left(1+a x+b x^{2}\right)(1-3 x)^{15}$ in powers of $x$, then the ordered pair $(a, b)$ is equal to:

  1. $(28,861)$

  2. $(-54,315)$

  3. $(28,315)$

  4. $(-21,714)$

Correct Option: 3

JEE Main Previous Year 1 Question of JEE Main from Mathematics Binomial Theorem and its Simple Applications chapter.
JEE Main Previous Year April 10, 2019(I)


Leave a Reply

Your email address will not be published. Required fields are marked *

error: Content is protected !!