If the cube roots of unity are 1, w, 2 w then the roots of the equation 3 ( –1) x + 8 = 0, are

Question:

If the cube roots of unity are $1, \omega, \omega^{2}$ then the roots of the equation $(x-1)^{3}+8=0$, are

  1. $-1,-1+2 \omega,-1-2 \omega^{2}$

  2. $-1,-1,-1$

  3. $-1,1-2 \omega, 1-2 \omega^{2}$

  4. $-1,1+2 \omega, 1+2 \omega^{2}$

Correct Option: 3

JEE Main Previous Year 1 Question of JEE Main from Mathematics Complex Numbers and Quadratic Equations chapter.
JEE Main Previous Year 2005

Solution:

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