**Question:**

**In a transverse wave the distance between a crest and neighbouring trough at the same instant is $4.0 \mathrm{~cm}$ and the distance between a crest and trough at the same place is $1.0 \mathrm{~cm}$. The next crest appears at the same place after a time interval of $0.4 \mathrm{~s}$. The maximum speed of the vibrating particles in the medium is :**

$\frac{3 \pi}{2} \mathrm{~cm} / \mathrm{s}$

$\frac{5 \pi}{2} \mathrm{~cm} / \mathrm{s}$

$\frac{\pi}{2} \mathrm{~cm} / \mathrm{s}$

$2 \pi \mathrm{cm} / \mathrm{s}$

Question of from chapter.

JEE Main Previous Year Online April 25, 2013

Correct Option: 2

**Solution:**

(2)