Question:
In a transverse wave the distance between a crest and neighbouring trough at the same instant is $4.0 \mathrm{~cm}$ and the distance between a crest and trough at the same place is $1.0 \mathrm{~cm}$. The next crest appears at the same place after a time interval of $0.4 \mathrm{~s}$. The maximum speed of the vibrating particles in the medium is :
$\frac{3 \pi}{2} \mathrm{~cm} / \mathrm{s}$
$\frac{5 \pi}{2} \mathrm{~cm} / \mathrm{s}$
$\frac{\pi}{2} \mathrm{~cm} / \mathrm{s}$
$2 \pi \mathrm{cm} / \mathrm{s}$
Question of from chapter.
JEE Main Previous Year Online April 25, 2013
Correct Option: 2
Solution:
(2)
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