# In terms of resistance $\mathrm{R}$ and time $\mathrm{T}$, the dimensions of ratio $\frac{\mu}{\varepsilon}$ of the permeability $\mu$ and permittivity $\varepsilon$ is:

Question:

In terms of resistance $\mathrm{R}$ and time $\mathrm{T}$, the dimensions of ratio $\frac{\mu}{\varepsilon}$ of the permeability $\mu$ and permittivity $\varepsilon$ is:

1. $\left[\mathrm{RT}^{-2}\right](\mathrm 2.$\left[\mathrm{R}^{2} \mathrm{~T}^{-1}\right]$3.$\left[\mathrm{R}^{2}\right]$4.$\left[\mathrm{R}^{2} \mathrm{~T}^{2}\right]$JEE Main Previous Year Single Correct Question of JEE Main from Physics Physical World, Units and Measurements chapter. JEE Main Previous Year April 11, 2014 Correct Option: 3 Solution: ### Related Questions •$\mathrm{A}, \mathrm{B}, \mathrm{C}$and$\mathrm{D}$are four different physical quantities having different dimensions. None of them is dimensionless. But we know that the equation$\mathrm{AD}=\mathrm{C} \ln (\mathrm{BD})$holds true. Then which of the combination is not a meaningful quantity? View Solution • In the following ‘I’ refers to current and other symbols have their usual meaning, Choose the option that corresponds to the dimensions of electrical conductivity: View Solution • If electronic charge e, electron mass$\mathrm{m}$, speed of light in vacuum$c$and Planck’s constant$h$are taken as fundamental quantities, the permeability of vacuum$\mu_{0}$can be expressed in units of: View Solution • If the capacitance of a nanocapacitor is measured in terms of a unit ‘$u$‘ made by combining the electric charge ‘$e$‘, Bohr radius ‘$\mathrm{a}_{0}$‘, Planck’s constant ‘$\mathrm{h}$‘ and speed of light$’ c$‘ then: View Solution • From the following combinations of physical constants (expressed through their usual symbols) the only combination, that would have the same value in different systems of units, is: View Solution • Let$\left[\epsilon_{0}\right]$denote the dimensional formula of the permittivity of vacuum. If$\mathrm{M}=$mass,$\mathrm{L}=$length,$\mathrm{T}=$time and$\mathrm{A}=$electric current, then: View Solution • If the time period$t$of the oscillation of a drop of liquid of density$d$, radius$r$, vibrating under surface tension$s$is given by the formula$t=\sqrt{r^{2 b} s^{c} d^{a / 2}}$. It is observed that the time period is directly proportional to$\sqrt{\frac{d}{s}}$. The value of$b$should therefore be View Solution • The dimensions of angular momentum, latent heat and capacitance are, respectively. View Solution • Given that$K=$energy,$V=$velocity,$T=$time. If they are chosen as the fundamental units, then what is dimensional formula for surface tension? View Solution • The dimensions of magnetic field in$\mathrm{M}, \mathrm{L}, \mathrm{T}$and$\mathrm{C}\$ (coulomb) is given as

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