Let 4 cos(α + β) 5 = and sin 5 (), 13 a-b = where π 0 α, β 4 £ £ . Then tan 2a =

Question:
Let $\cos (\alpha+\beta)=\frac{4}{5}$ and $\sin (\alpha-\beta)=\frac{5}{13}$, where $0 \leq \alpha, \beta \leq \frac{\pi}{4}$. Then $\tan 2 \alpha=$

$\frac{56}{33}$
$\frac{19}{12}$
$\frac{20}{7}$
$\frac{25}{16}$

Correct Option: 1

JEE Main Previous Year 1 Question of JEE Main from Mathematics Trigonometry chapter.

JEE Main Previous Year 2010

Solution:

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