Let f be an odd function defined on the set of real numbers such that for x ³ 0, f(x) = 3 sin x + 4 cos x. Then f(x) at x = 11 6 p – is equal to:

Question:

Let $f$ be an odd function defined on the set of real numbers such that for $x \geq 0, f(x)=3 \sin x+4 \cos x$.

Then $\mathrm{f}(\mathrm{x})$ at $\mathrm{x}=-\frac{11 \pi}{6}$ is equal to: 

  1. $\frac{3}{2}+2 \sqrt{3}$

  2. $-\frac{3}{2}+2 \sqrt{3}$

  3. $\frac{3}{2}-2 \sqrt{3}$

  4. $-\frac{3}{2}-2 \sqrt{3}$


Correct Option: 3

JEE Main Previous Year 1 Question of JEE Main from Mathematics Sets, Relations and Functions chapter.
JEE Main Previous Year Online April 11, 2014

Solution:

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