**Question:**

Let the sum of the first $n$ terms of a non-constant A.P., $a_{1}, a_{2}, a_{3}, \ldots \ldots \ldots \ldots .$ be $50 n+\frac{n(n-7)}{2} A$, where $A$ is a constant. If $d$ is the common difference of this A.P., then the ordered pair $\left(\mathrm{d}, \mathrm{a}_{50}\right)$ is equal to: $\quad$

Correct Option: 4

JEE Main Previous Year April 09, 2019 (I)

**Solution:**