Mobility of electrons in a semiconductor is defined as the ratio of their drift velocity to the applied electric field. If, for an n-type semiconductor, the density of electrons is 1019 m – 3 and their mobility is 1.6m2 /(V.s) then the resistivity of the semiconductor (since it is an n-type semiconductor contribution of holes is ignored) is close to:

Question:

Mobility of electrons in a semiconductor is defined as the ratio of their drift velocity to the applied electric field. If, for an $\mathrm{n}$-type semiconductor, the density of electrons is $10^{19} \mathrm{~m}^{-}$ ${ }^{3}$ and their mobility is $1.6 \mathrm{~m}^{2} /$ (V.s) then the resistivity of the semiconductor (since it is an n-type semiconductor contribution of holes is ignored) is close to:

  1. $2 \Omega \mathrm{m}$

  2. $4 \Omega \mathrm{m}$

  3. $0.4 \Omega \mathrm{m}$

  4. $0.2 \Omega \mathrm{m}$


Correct Option: 3

JEE Main Previous Year 1 Question of JEE Main from Physics Semiconductor Electronics : Materials, Devices and Simple Circuits chapter.
JEE Main Previous Year 9 Jan. 2019I

Solution:

Leave a Reply

Your email address will not be published. Required fields are marked *

error: Content is protected !!