The number of ordered pairs (r, k) for which 6.35Cr = (k 2 – 3).36Cr + 1, where k is an integer, is:

Question:

The number of ordered pairs $(r, k)$ for which $6 \cdot{ }^{35} C_{r}$ $=\left(k^{2}-3\right) \cdot{ }^{36} C_{r+1}$, where $k$ is an integer, is:

  1. 3

  2. 2

  3. 6

  4. 4


Correct Option: 4

JEE Main Previous Year 1 Question of JEE Main from Mathematics Permutations And Combinations chapter.
JEE Main Previous Year Jan. 7, 2020 (II)

Solution:

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