The value of 19 n 1 n1 p1 cot cot 1 2p – = = æ ö æ ö ç ÷ ç ÷ + è ø è ø å å is:

Question:

The value of $\cot \left(\sum_{n=1}^{19} \cot ^{-1}\left(1+\sum_{p=1}^{n} 2 p\right)\right)$ is:

  1. $\frac{21}{19}$

  2. $\frac{19}{21}$

  3. $\frac{22}{23}$

  4. $\frac{23}{22}$


Correct Option: 1

JEE Main Previous Year 1 Question of JEE Main from Mathematics Inverse Trigonometric Functions chapter.
JEE Main Previous Year Jan. 10, 2019 (II)

Solution:

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