Question:
The value of acceleration due to gravity is $g_{1}$ at a height $h=\frac{R}{2}(R=$ radius of the earth $)$ from the surface of the earth. It is again equal to $g_{1}$ and a depth $d$ below the surface of the earth. The ratio $\left(\frac{d}{R}\right)$ equals :
$\frac{4}{9}$
$\frac{5}{9}$
$\frac{1}{3}$
$\frac{7}{9}$
Question of from chapter.
JEE Main Previous Year 5 Sep. 2020 (I)
Correct Option: 2
Solution:
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