**Question:**

**The value of acceleration due to gravity is $g_{1}$ at a height $h=\frac{R}{2}(R=$ radius of the earth $)$ from the surface of the earth. It is again equal to $g_{1}$ and a depth $d$ below the surface of the earth. The ratio $\left(\frac{d}{R}\right)$ equals :**

$\frac{4}{9}$

$\frac{5}{9}$

$\frac{1}{3}$

$\frac{7}{9}$

Question of from chapter.

JEE Main Previous Year 5 Sep. 2020 (I)

Correct Option: 2

**Solution:**