**Question:**

**There is a circular tube in a vertical plane. Two liquids which do not mix and of densities $d_{1}$ and $d_{2}$ are filled in the tube. Each liquid subtends $90^{\circ}$ angle at centre. Radius joining their interface makes an angle $\alpha$ with vertical. Ratio $\frac{\mathrm{d}_{1}}{\mathrm{~d}_{2}}$ is:**

$\frac{1+\sin \alpha}{1-\sin \alpha}$

$\frac{1+\cos \alpha}{1-\cos \alpha}$

$\frac{1+\tan \alpha}{1-\tan \alpha}$

$\frac{1+\sin \alpha}{1-\cos \alpha}$

Question of from chapter.

JEE Main Previous Year 2014

Correct Option: 3

**Solution:**

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