# Time ( $\mathrm{T}$ ), velocity ( $\mathrm{C}$ ) and angular momentum (h) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be:

Question:

Time ( $\mathrm{T}$ ), velocity ( $\mathrm{C}$ ) and angular momentum (h) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be:

1. $[\mathrm{M}]=\left[\mathrm{T}^{-1} \mathrm{C}^{-2} \mathrm{~h}\right]$

2. $[\mathrm{M}]=\left[\mathrm{T}^{-1} \mathrm{C}^{2} \mathrm{~h}\right]$

3. $[\mathrm{M}]=\left[\mathrm{T}^{-1} \mathrm{C}^{-2} \mathrm{~h}^{-1}\right]$

4. $[\mathrm{M}]=\left[\mathrm{T} \mathrm{C}^{-2} \mathrm{~h}\right]$

JEE Main Previous Year Single Correct Question of JEE Main from Chemistry Laws of Motion chapter.

JEE Main Previous Year April 8, 2017

Correct Option: 1

Solution:

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