Question:
Two blocks $A$ and $B$ masses $m_{A}=1 \mathrm{~kg}$ and $m_{B}=3 \mathrm{~kg}$ are kept on the table as shown in figure. The coefficient of friction between $\mathrm{A}$ and $\mathrm{B}$ is $0.2$ and between $\mathrm{B}$ and the surface of the table is also $0.2$. The maximum force $\mathrm{F}$ that can be applied on B horizontally, so that the block A does not slide over the block B is: [Take $g=10 \mathrm{~m} / \mathrm{s}^{2}$ ]
$8 \mathrm{~N}$
$16 \mathrm{~N}$
$40 \mathrm{~N}$
$12 \mathrm{~N}$
Question of from chapter.
JEE Main Previous Year 10 April 2019
Correct Option: 2
Solution:
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