Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated?

Question:
Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated?

$2 ! 3 ! 4 !$
$(3 !)^{3} \cdot(4 !)$
$(3 !)^{2} \cdot(4 !)$
$3 !(4 !)^{3}$

Correct Option: 2

JEE Main Previous Year 1 Question of JEE Main from Mathematics Permutations And Combinations chapter.

JEE Main Previous Year Sep. 06, 2020 (I)

Solution:

Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated?

Question:
Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated?

$2 ! 3 ! 4 !$
$(3 !)^{3} \cdot(4 !)$
$(3 !)^{2} \cdot(4 !)$
$3 !(4 !)^{3}$

Correct Option: 2

JEE Main Previous Year 1 Question of JEE Main from Mathematics Permutations And Combinations chapter.

JEE Main Previous Year Sep. 06, 2020 (I)

Solution:

Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated?

Leave a Reply Cancel reply

Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same family members are not separated?

Leave a Reply Cancel reply