Two identical capacitors A and B, charged to the same potential 5V are connected in two different circuits as shown below at time t = 0. If the charge on capacitors A and B at time t = CR is QA and QB respectively, then (Here e is the base of natural logarithm)

Question:

Two identical capacitors A and B, charged to the same potential $5 \mathrm{~V}$ are connected in two different circuits as shown below at time $t=0$. If the charge on capacitors A and $\mathrm{B}$ at time $t=\mathrm{CR}$ is $\mathrm{Q}_{\mathrm{A}}$ and $\mathrm{Q}_{\mathrm{B}}$ respectively, then (Here e is the base of natural logarithm)

  1. $\mathrm{Q}_{\mathrm{A}}=\frac{\mathrm{VC}}{e}, \mathrm{Q}_{\mathrm{B}}=\frac{\mathrm{CV}}{2}$

  2. $\mathrm{Q}_{\mathrm{A}}=\mathrm{VC}, \mathrm{Q}_{\mathrm{B}}=\mathrm{CV}$

  3. $\mathrm{Q}_{\mathrm{A}}=\mathrm{VC}, \mathrm{Q}_{\mathrm{B}}=\frac{\mathrm{VC}}{e}$

  4. $\mathrm{Q}_{\mathrm{A}}=\frac{\mathrm{CV}}{2}, \mathrm{Q}_{\mathrm{B}}=\frac{\mathrm{VC}}{e}$


Correct Option: 3

JEE Main Previous Year 1 Question of JEE Main from Physics Semiconductor Electronics : Materials, Devices and Simple Circuits chapter.
JEE Main Previous Year 9 Jan. 2020 II

Solution:

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