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The magnitude of the average electric field normally present in the atmosphere just above the surface of the Earth is about $150 \mathrm{~N} / \mathrm{C}$, directed inward towards the center of the Earth. This gives the total net surface charge carried by the Earth to be:

[Given $\varepsilon_{0}=8.85 \times 10^{-12} \mathrm{C}^{2} / \mathrm{N}-\mathrm{m}^{2}, \mathrm{R}_{\mathrm{E}}=6.37 \times 10^{6} \mathrm{~m}$ ]

  1. $+670 \mathrm{kC}$

  2. $-670 \mathrm{kC}$

  3. $-680 \mathrm{kC}$

  4. $+680 \mathrm{kC}$

Correct Option: 3


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