Question:
Which one of the following represents the correct dimensions of the coefficient of viscosity?
$\left[\mathrm{ML}^{-1} \mathrm{~T}^{-1}\right]$
$\left[\mathrm{MLT}^{-1}\right]$
$\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]$
$\left[\mathrm{ML}^{-2} \mathrm{~T}^{-2}\right]$
Question of from chapter.
JEE Main Previous Year 2004
Correct Option: 1
Solution:
Download now India’s Best Exam Preparation App
Class 9-10, JEE & NEET
Related Questions
$\mathrm{A}, \mathrm{B}, \mathrm{C}$ and $\mathrm{D}$ are four different physical quantities having different dimensions. None of them is dimensionless. But we know that the equation $\mathrm{AD}=\mathrm{C} \ln (\mathrm{BD})$ holds true. Then which of the combination is not a meaningful quantity?
In the following ‘I’ refers to current and other symbols have their usual meaning, Choose the option that corresponds to the dimensions of electrical conductivity:
If electronic charge e, electron mass $\mathrm{m}$, speed of light in vacuum $c$ and Planck’s constant $h$ are taken as fundamental quantities, the permeability of vacuum $\mu_{0}$ can be expressed in units of:
If the capacitance of a nanocapacitor is measured in terms of a unit ‘ $u$ ‘ made by combining the electric charge ‘ $e$ ‘, Bohr radius ‘ $\mathrm{a}_{0}$ ‘, Planck’s constant ‘ $\mathrm{h}$ ‘ and speed of light $’ c$ ‘ then:
From the following combinations of physical constants (expressed through their usual symbols) the only combination, that would have the same value in different systems of units, is:
In terms of resistance $\mathrm{R}$ and time $\mathrm{T}$, the dimensions of ratio $\frac{\mu}{\varepsilon}$ of the permeability $\mu$ and permittivity $\varepsilon$ is:
Let $\left[\epsilon_{0}\right]$ denote the dimensional formula of the permittivity of vacuum. If $\mathrm{M}=$ mass, $\mathrm{L}=$ length, $\mathrm{T}=$ time and $\mathrm{A}=$ electric current, then:
If the time period $t$ of the oscillation of a drop of liquid of density $d$, radius $r$, vibrating under surface tension $s$ is given by the formula $t=\sqrt{r^{2 b} s^{c} d^{a / 2}}$. It is observed that the time period is directly proportional to $\sqrt{\frac{d}{s}}$. The value of $b$ should therefore be
The dimensions of angular momentum, latent heat and capacitance are, respectively.
Given that $K=$ energy, $V=$ velocity,$T=$ time. If they are chosen as the fundamental units, then what is dimensional formula for surface tension?