On this page you will find Maths RD Sharma Class 9 Number System Exercise 1.3 Solutions. The solutions provided here are to help students practice math problems and get better at solving difficult chapter questions. Maths chapter 1 for class 9 deals with the topic of triangles and it is one of the most important chapters.

**Download RD Sharma Class 9 Number System Exercise 1.3 Solutions in PDF**

Students can use these solutions to overcome the fear of maths and the solutions have been designed in such a way that it enables them to discover easy ways to solve different problems. These solutions can help students in refining their maths fluency and problem-solving skills. Students can go through the RD Sharma solutions for class 9 chapter 1 Number System Exercise 1.3 below and it will be beneficial for them.

**RD Sharma Class 9 Number System Exercise 1.3 Solution**

**Q1. Express each of the following decimals in the form of rational number.
**

**(i) $0.39$**

**(ii) $0.750$**

**(iii) $2.15$**

**(iv) $7.010$**

**(v) $9.90$**

**(vi) $1.0001$**

*Solution:*

(i) Given,

$0.39=\frac{39}{100}$

(ii) Given,

$0.750=\frac{750}{1000}$

(iii) Given,

$2.15=\frac{215}{100}$ (iv) Given, $9.101$

(iv) Given,

$7.010=\frac{7010}{1000}$

(v) Given,

$9.90=\frac{990}{100}$

(vi) Given,

$1.0001=\frac{10001}{10000}$

**Q2. Express each of the following decimals in the form of rational number $\left(\frac{p}{q}\right)$
(i) $0 . \overline{4}$**

**(ii) $0 . \overline{37}$**

*Solution:*

Multiplying both sides of equation (a) by 10 , we get

Subtracting equation (1) by $(2)$

Multiplying both sides of equation (a) by 100, we get,

Subtracting equation (1) by $(2)$

$99 x=37$

$x=\frac{37}{99}$